Answer
The coefficient of static friction must be at least $\mu_s = 0.55$
Work Step by Step
$v = (95 \frac{km}{h})(\frac{1000 ~m}{1 ~km})(\frac{1 ~h}{3600 ~s})$
$v = 26 ~m/s$
As long as the coefficient of static friction is high enough, the force of static friction provides the necessary force to round the curve.
$F_f = m \frac{v^2}{r}$
$mg ~\mu_s = m \frac{v^2}{r}$
$\mu_s = \frac{v^2}{gr}$
$\mu_s = \frac{(26 ~m/s)^2}{(9.8 ~m/s^2)(125 ~m)}$
$\mu_s = 0.55$
Therefore, the coefficient of static friction must be at least $\mu_s = 0.55$
