Answer
34 m/s
Work Step by Step
$F_{normal}=F_{gravity}+F_{centripetal}$
At the bottom of the hill,
$2(F_{normal})=F_{gravity}+F_{centripetal}$
$2(m(9.81))=\frac{mv^{2}}{115}+m(9.81)$
$2(9.81)=\frac{v^{2}}{115}+9.81$
$v^{2}=1128.15$
$v=34m/s^{2}$
The answer is displayed to 2 significant figures.