Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems: 3


12 m/s.

Work Step by Step

The net horizontal force is the centripetal force that causes the circular motion. $$F_{net}=310 N = ma_R=\frac{mv^2}{r}=\frac{(2.0 kg)(v)^2}{0.90 m} $$ $$v=\sqrt{\frac{(310 N)(0.90 m)}{2.0 kg}} \approx 12 m/s$$ The answer is displayed to 2 significant figures.
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