Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 132: 12

Answer

(a) The minimum radius is 920 meters. (b) F = 5400 N (c) F = 3800 N

Work Step by Step

(a) $v = (840 ~km/h)(\frac{1000 ~m}{1 ~km})(\frac{1 ~h}{3600 ~s}) = 233 ~m/s$ $a = \frac{v^2}{r}$ $r = \frac{v^2}{a} = \frac{(233 ~m/s)^2}{(6.0)(9.80 ~m/s^2)}$ $r = 920 ~m$ The minimum radius is 920 meters. (b) Let $F_s$ be the force of the seat pushing up on the pilot. $\sum F = ma$ $F_s - mg = m(6.0g)$ $F_s = (7.0)(mg) = (7.0)(78 ~kg)(9.80 ~m/s^2)$ $F_s = 5400~N$ (c) $\sum F = ma$ $F_s + mg = m(6.0g)$ $F_s = (5.0)(mg) = (5.0)(78 ~kg)(9.80 ~m/s^2)$ $F_s = 3800~N$
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