Answer
$4.9\times10^{-5}rem$.
Work Step by Step
Over the 1.4 hours of exposure, assume that the activity is constant, since the half-life is stated as 30 years.
First, calculate the total energy absorbed. The table on page 901 shows that the Relative Biological Effectiveness (RBE) of beta particles and of gamma rays is 1.
Therefore, we can simply add their energies: 660keV+190keV=850keV.
The definition of a curie is $3.7\times10^{10}$ decays/s.
$$E=(1.2\times10^{-6}Ci)( 3.7\times10^{10}\frac{decays}{s})(1.4h)\frac{3600s}{h}\frac{850\times10^3 eV}{decay}\frac{1.60\times10^{-19}J}{eV}$$
$$=3.043\times10^{-5}J$$
Finally, calculate the effective dose.
$$dose=\frac{3.043\times10^{-5}J }{62kg}\frac{100rad}{1J/kg}=4.9\times10^{-5}rad\approx 4.9\times10^{-5}rem$$
