Answer
The Q-value is calculated using equation 31-2a.
Work Step by Step
$$Q=3m_{_{2}^{4}He }c^2- m_{_{6}^{12}C }c^2$$
$$=(3(4.002603u)-12.000000u)(931.5\frac{MeV/c^2}{u})c^2=7.274MeV$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - General Problems - Page 913: 69
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