Answer
See answers.
Work Step by Step
a. The definition of a curie is $3.7\times10^{10}$ decays/s.
$$(0.10\times10^{-6}Ci)( 3.7\times10^{10}\frac{decays}{s})=3700\frac{decays}{s}$$
b. The table on page 901 shows that the Relative Biological Effectiveness (RBE) of beta particles is 1.
Calculate the dose in Gy and then convert to Sv. The half-life is so long that we may assume that the activity is constant.
$$(3700\frac{decays}{s})\frac{1.4MeV}{decay}\frac{1.60\times10^{-13}J}{MeV}(3.156\times10^7 s/y)\frac{1}{65kg}$$
$$=4.0\times10^{-4}Sv/y$$
Compare this to the background rate that is given.
$$\frac{4.024\times10^{-4}Sv/y}{3.6\times10^{-3}Sv/y}=0.11$$
It is about $11\%$ of the background rate, which is significant.
