Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - General Problems - Page 913: 56

Answer

$8.620\times10^{-8}\frac{keV}{K}$

Work Step by Step

Use the relation KE = kT. To convert from kelvins to keV, use the Boltzmann constant, expressed in the proper units. $$k=(1.381\times10^{-23}\frac{J}{K})(\frac{1\;eV}{1.602\times10^{-19}J})(\frac{1\;keV}{1000\;eV})$$ $$k=8.620\times10^{-8}\frac{keV}{K}$$
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