Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 28 - Quantum Mechanics of Atoms - Problems - Page 827: 41

Answer

The pulse energy is 0.017 J, and there are $5.5\times10^{16}$ photons per pulse.

Work Step by Step

The energy per pulse is the average power multiplied by the duration. $$E=P\Delta t=(0.68W)(25\times10^{-3}s)=0.017J$$ The number of photons contained in a pulse is the energy of a pulse, divided by the energy of a single photon of that frequency. Use equation 27–4. $$N=\frac{E}{hf}=\frac{E\lambda}{hc}=\frac{(0.017J)(640\times10^{-9}m)}{(6.626\times10^{-34}J \cdot s)(3.00\times10^{8}m/s)}$$ $$= 5.5\times10^{16}photons $$ The pulse energy is 0.017 J, and there are $5.5\times10^{16}$ photons per pulse.
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