Answer
See answers.
Work Step by Step
For oxygen, Z = 8. We start with $n=1$, and list the quantum numbers in the order $(n, \mathcal{l}, m_{\mathcal{l}}, m_s)$.
See the figure for the list of quantum numbers for the electrons in oxygen’s ground state.
Not enough information is provided to uniquely identify the final 4 electrons. There are 2 other possibilities (where the third quantum number $ m_{\mathcal{l}}=1$) that can substitute for any of the final four states.
