Answer
0.659 c
Work Step by Step
Use equation 26–5b.
$$KE=(\gamma-1)mc^2=0.33mc^2$$
$$\frac{1}{\sqrt{1-v^2/c^2}}-1=0.33$$
$$v=c\sqrt{1-\frac{1}{(1.33^2)}}=0.659c$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 30
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