Answer
$ 5.36\times10^{-13}kg $
Work Step by Step
The mass increase is found by using equation 26–8.
$$\Delta E=\Delta mc^2$$
$$\Delta m=\frac{\Delta E}{c^2}=\frac{4.82\times10^{4}J}{(3.00\times10^8m/s)^2}$$
$$=5.36\times10^{-13}kg $$
This is a tiny mass change, and $\Delta m$ is generally neglected in chemical reactions.
