Answer
0.9497c.
Work Step by Step
The kinetic energy is given by equation 26–5b. Find $\gamma$.
$$KE=1.12MeV=(\gamma-1)mc^2=(\gamma-1)(0.511MeV)$$
$$\gamma = 3.192$$
Use equation 26-2 to solve for the corresponding v.
$$\gamma=\frac{1}{\sqrt{1-v^2/c^2}}=3.192$$
$$v/c=\sqrt{1-(1/\gamma)^2}=0.9497$$
$$v =0.9497c$$
