Answer
$4\times10^{-28}kg $
Work Step by Step
The mass loss is found by using equation 26–7.
$$E=mc^2$$
$$m=\frac{E}{c^2}=\frac{(200MeV)(1.60\times10^{-13}J/MeV)}{(3.00\times10^8m/s)^2}$$
$$=3.56\times10^{-28}kg\approx 4\times10^{-28}kg $$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 22
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