Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 741: 55

Answer

$1.7\times10^{11}m$

Work Step by Step

Find the angular resolution using equation 25–7. $$\theta=\frac{1.22\lambda}{D}$$ The distance between the stars, L, is that angle multiplied by the distance to the stars from the Earth, r. $$L=r \theta=1.22\frac{r \lambda}{D}$$ $$L= 1.22 \frac{(18ly)(9.46\times10^{15}m/ly)(550\times10^{-9}m)}{0.66m}$$ $$L= 1.7\times10^{11}m$$
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