Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 741: 37

Answer

$M=-110$

Work Step by Step

The focal length of the mirror (the objective) is half the radius of curvature. $$f = \frac{r}{2} = \frac{6.1m}{2} = 3.05m\approx 3.1m$$ Use equation 25-3 to find the magnification of the telescope. $$M=-\frac{f_o}{f_e}=-\frac{0.5(6.1m)}{0.028m}\approx-110$$
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