Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 741: 38

Answer

$f_o \approx4.7m$ $r= 9.3m$

Work Step by Step

Use equation 25-3 to find the magnification of the telescope. The objective is a converging mirror, with positive focal length. The magnification is negative. $$M=-\frac{f_o}{f_e}$$ $$f_o=-Mf_e=-(-150)(0.031m)=4.65m \approx4.7m$$ The focal length of the mirror (the objective) is half the radius of curvature, f = r/2. Double the focal length to find the radius of curvature. $$r= 2f = 9.3m$$
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