Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 741: 54

Answer

$1\times10^{-6}m$

Work Step by Step

$$RP=\frac{1.22\lambda f}{D}=\frac{(1.22)(550\times10^{-9}m)(9mm)}{5mm}$$ $$RP=1.21\times10^{-6}m\approx 1\times10^{-6}m$$
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