Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 741: 46

Answer

a) $M=840X$ b) $f_e=1.79cm$ $f_o=0.299cm$ c) $d_o=0.304cm$

Work Step by Step

a) $M=M_em_o=14.0X\times60.0X=840X$ b) $f_e=\frac{N}{M_e}=\frac{25.0cm}{14.0X}=1.786cm$ $d_i=l-f_e=20.0cm-1.786cm=18.21cm$ $d_o=\frac{d_i}{m}=\frac{18.21cm}{60.0X}=0.304cm$ $\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{18.21cm}+\frac{1}{0.304cm}=0.299cm$ c) $d_o=\frac{d_i}{m}=\frac{18.21cm}{60.0X}=0.304cm$
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