Answer
$M_{largest}=615X$
$M_{smallest}=25X$
Work Step by Step
$M_{largest}=\frac{160mm}{3.9mm}\times15X=615X$
$M_{smallest}=\frac{160mm}{32mm}\times5X=25X$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 25 - Optical Instruments - Problems - Page 741: 50
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