Answer
a. Center
b. Real
c. Inverted
d. -1.00
Work Step by Step
Use the mirror equation, 23–2.
$$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$
a. We are told that $d_o=d_i$.
$$\frac{1}{d_o}+\frac{1}{d_o}=\frac{1}{f}$$
$$\frac{2}{d_o}=\frac{1}{f}$$
$$d_o=2f=r$$
The object should be placed at the mirror's center of curvature.
b. The image is in front of the mirror, where the object is, so $d_i\gt 0$ and the image is real.
c, d. Calculate the magnification.
$$m=-\frac{d_i}{d_o}=-\frac{d_o}{d_o}=-1.00$$
The magnification is negative one, so the image is inverted and the same size as the object.
