Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 14

Answer

Convex; -38.0 cm.

Work Step by Step

Use the mirror equation, 23–2. $$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$ Here, the object is at $d_o=\infty$. $$\frac{1}{\infty}+\frac{1}{d_i}=\frac{1}{f}$$ Solve for the focal length. The image distance is a negative number, because the image is behind the mirror. $$f=d_i=-19.0cm$$ The radius is twice the focal length, or $r = -38.0cm$. The focal length is negative, so the mirror is convex, aka a diverging mirror.
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