Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 18

Answer

Convex; -16 m.

Work Step by Step

The mirror is convex. Concave mirrors don’t produce images that are upright and smaller than the object. The object distance is 16.0 m. The magnification is +0.33. Find the image distance, then the focal length. $$m=-\frac{d_i}{d_o}$$ $$d_i=-md_o$$ Use the mirror equation, 23–2. $$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$ Solve for the focal length. $$f=\frac{d_od_i}{d_o+d_i}=\frac{d_o(-md_o)}{d_o-md_o}$$ $$=\frac{(16.0m)(-(0.33)16.0m)}{16.0m-0.33(16.0m)}=-7.881m$$ The negative focal length f confirms that the mirror is indeed convex. The radius is twice the focal length, or $r=-16m$.
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