Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 13

Answer

-6.8 m

Work Step by Step

The object distance is 3.4 m. The magnification is +0.5. Find the image distance, then the focal length. $$m=-\frac{d_i}{d_o}$$ $$d_i=-md_o$$ Use the mirror equation, 23–2. $$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$ Solve for the focal length. $$f=\frac{d_od_i}{d_o+d_i}=\frac{d_o(-md_o)}{d_o-md_o}$$ $$=\frac{(3.4m)(-(0.5)3.4m)}{3.4m-0.5(3.4m)}=-3.4m$$ The radius is twice the focal length, or -6.8m.
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