Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 12

Answer

The focal length is 2.677 cm and the radius is 5.3 m.

Work Step by Step

The object distance is 2.00 cm. The magnification is +4. Find the image distance, then the focal length. $$m=-\frac{d_i}{d_o}$$ $$d_i=-md_o$$ Use the mirror equation, 23–2. $$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$ Solve for the focal length. $$f=\frac{d_od_i}{d_o+d_i}=\frac{d_o(-md_o)}{d_o-md_o}$$ $$=\frac{(2.0cm)(-(4)2.0cm)}{2.0cm-4(2.0cm)}=2.677cm$$ The radius is twice the focal length, or 5.3 cm. The focal length is positive, so the mirror is concave, aka a converging mirror.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.