Answer
$1.6\times10^4W$
Work Step by Step
Calculate the rate of heat flow using equation 14–5.
$$\frac{Q}{t}=kA\frac{T_1-T_2}{\mathcal{l}}$$
$$=(\frac{0.84 J}{s \cdot m \cdot C^{\circ}})(3.0m^2)\frac{15.0^{\circ}C-(-5^{\circ}C)}{3.2\times10^{-3}m}$$
$$=1.6\times10^4W$$
