Answer
(a) The energy absorbed from the body is $5.2\times 10^5~J$
(b) The energy absorbed from the body is $1.5\times 10^5~J$
Work Step by Step
(a) We can find the energy required to warm the snow up to $37^{\circ}C$.
$Q = m~c_i~\Delta T_i+m~L + m~c_w~\Delta T_w$
$Q = (1.0~kg)(2100~J/kg~C^{\circ})(15~C^{\circ})+ (1.0~kg)(3.33\times 10^5~J/kg) + (1.0~kg)(4186~J/kg~C^{\circ})(37~C^{\circ})$
$Q = 5.2\times 10^5~J$
The energy absorbed from the body is $5.2\times 10^5~J$.
(b) We can find the energy required to warm the water up to $37^{\circ}C$.
$Q = m~c_w~\Delta T_w$
$Q = (1.0~kg)(4186~J/kg~C^{\circ})(37~^{\circ}C - 2~^{\circ}C)$
$Q = 1.5\times 10^5~J$
The energy absorbed from the body is $1.5\times 10^5~J$.
