Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 14 - Heat - Problems - Page 409: 22

Answer

The calorie content of 65 grams of candy is 326 kcal

Work Step by Step

The energy $Q$ required to raise the temperature of a substance is: $Q = mc~\Delta T$ We can find the heat energy gained by the water and the aluminum. $Q = m_w~c_w~\Delta T + m_a~c_a~\Delta T$ $Q = (1.75~kg)(4186~J/kg~C^{\circ})(53.5~^{\circ}C-15.0~^{\circ}C) + (0.325~kg+0.624~kg)(900~J/kg~C^{\circ})(53.5~^{\circ}C-15.0~^{\circ}C) $ $Q = 314,914.6~J$ This amount of energy is the energy released by the 15 grams of candy. We can convert the energy to units of calories. $Q = (314,914.6~J)(\frac{1~cal}{4.186~J})$ $Q = 75,230~cal = 75.23~kcal$ We can find the calorie content per gram of the candy. $\frac{75.23~kcal}{15~g} = 5.015~kcal/g$ We can find the calorie content of 65 grams of candy. $(5.015~kcal/g)(65~g) = 326~kcal$ The calorie content of 65 grams of candy is 326 kcal.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.