Answer
a. $C= mc $
b. $4.2\times10^3\frac{J}{C^{\circ}}$
c. $1.9\times10^5\frac{J}{C^{\circ}}$
Work Step by Step
a. We know that $Q=C \Delta T$, and $Q=mc\Delta T$, so $C= mc $.
b. For 1.0 kg of water, $C=mc=(1.0kg)(\frac{4186J}{kg\cdot C^{\circ}})=4.2\times10^3\frac{J}{C^{\circ}}$.
c. For 45 kg of water, $C=mc=(45kg)(\frac{4186J}{kg\cdot C^{\circ}})=1.9\times10^5\frac{J}{C^{\circ}}$.
