Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 14 - Heat - Problems - Page 409: 23

Answer

The calorie content of 100 grams of cookie is 471 kcal.

Work Step by Step

The energy $Q$ required to raise the temperature of a substance is: $Q = mc~\Delta T$ We can find the heat energy gained by the water and the aluminum. $Q = m_w~c_w~\Delta T + m_a~c_a~\Delta T$ $Q = (2.00~kg)(4186~J/kg~C^{\circ})(36.0~^{\circ}C-15.0~^{\circ}C) + (0.615~kg+0.524~kg)(900~J/kg~C^{\circ})(36.0~^{\circ}C-15.0~^{\circ}C) $ $Q = 197,339.1~J$ This amount of energy is the energy released by the 10 grams of cookie. We can convert the energy to units of calories. $Q = (197,339.1~J)(\frac{1~cal}{4.186~J})$ $Q = 47,100~cal = 47.1~kcal$ We can find the calorie content per gram of the cookie. $\frac{47.1~kcal}{10~g} = 4.71~kcal/g$ We can find the calorie content of 100 grams of cookie. $(4.71~kcal/g)(100~g) = 471~kcal$ The calorie content of 100 grams of cookie is 471 kcal.
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