Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 30 - Electromagnetic Induction - Exercises and Problems - Page 870: 23

Answer

2400

Work Step by Step

Given that $V_{p}=120V$, $V_{s}=3.0 V$ and $N_{s}= 60$. We know that $\frac{V_{s}}{V_{p}}=\frac{N_{s}}{N_{p}}$ $\implies N_{p}=\frac{V_{p}N_{s}}{V_{s}}=\frac{120V\times60}{3.0V}=2400$
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