Chapter 30 - Electromagnetic Induction - Exercises and Problems - Page 870: 16

$emf = 1.6~V$

We can find the $emf$ of the coil: $emf = N~\frac{d\phi}{dt}$ $emf = \frac{N \Delta B~A}{\Delta t}$ $emf = \frac{N~\Delta B~\pi~r^2}{\Delta t}$ $emf = \frac{(1000)(0.20~T)~(\pi)~(5.0\times 10^{-3}~m)^2}{10\times 10^{-3}~s}$ $emf = 1.6~V$