Answer
(a) $0.732atm$
(b) $0.52atm$
Work Step by Step
(a) We can determine the required pressure as follows:
$p=\frac{T}{T_{\circ}}p_{\circ}$
We plug in the known values to obtain:
$p=\frac{273}{373}\cdot 1atm=0.732atm$
(b) For insulated box filled with dry ice, we can determine the required pressure as follows:
$p=\frac{T}{T_{\circ}}p_{\circ}$
We plug in the known values to obtain:
$p=\frac{194}{373}\cdot 1atm$
$\implies p=0.52atm$