Answer
(a) $607.8Pa;32.018 F^{\circ}$
(b) $-68.8F^{\circ};506500Pa$
Work Step by Step
(a) We know that at triple point $T=0.01C^{\circ}$ and the pressure is $p=0.006 atm$
Now the temperature in $F^{\circ}$ and pressure in $Pa$ is given as
$T_F=1.8T_C+32$
$\implies T_F=1.8(0.01C^{\circ})+32$
$\implies T_F=32.018 F^{\circ}$
and $P=101300(0.006)=607.8Pa$
(b) We know that at triple point for carbon dioxide $T=-56C^{\circ}$ and the pressure is $p=5 atm$
Now the temperature in $F^{\circ}$ and pressure in $Pa$ is given as
$T_F=1.8T_C+32$
$T_F=1.8(-56)+32=-68.8F^{\circ}$
and $p=101300(5)=506500Pa$
