## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

a) $T_{2}$ = $T_{1}$ b) $p_{2}$ = $\frac{p_{1}}{2}$
a) This is an Isothermal process which means that temperature is constant: $T_{2}$ = $T_{1}$ b) We can use the ideal gas law to find $p_{2}$ : $\frac{p_{1}V_{1}}{T_{1}}$ = $\frac{p_{2}V_{2}}{T_{2}}$ Where: $p_{1}$ is the initial pressure $p_{2}$ is the final pressure $T_{1}$ is the initial temperature $T_{2}$ is the final temperature $V_{1}$ is the initial volume $V_{2}$ is the final volume So: $p_{2}$ = $\frac{p_{1}V_{1}T_{2}}{V_{2}T_{1}}$ = $\frac{p_{1}V_{1}T_{1}}{2V_{1}T_{1}}$ = $\frac{p_{1}}{2}$