## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 464: 12

#### Answer

The numerical value in $^{\circ}F$ matches numerical value in $^{\circ}C$ when the temperature is $-40^{\circ}F$ (which is equal to $-40^{\circ}C$)

#### Work Step by Step

We can use the equation to convert from Fahrenheit to Celsius to solve for F when C = F; $C = \frac{5}{9}(F-32)$ $F = \frac{5}{9}(F-32)$ $9F = 5F-160$ $4F = -160$ $F = -40$ The numerical value in $^{\circ}F$ matches numerical value in $^{\circ}C$ when the temperature is $-40^{\circ}F$ (which is equal to $-40^{\circ}C$).

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