Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 464: 16

Answer

$1.9MPa$

Work Step by Step

We can determine the gas pressure as follows: $pV=nRT$ This can be rearranged as: $p=\frac{nRT}{V}$ We plug in the known values to obtain: $p=\frac{(3)(8.31)(153)}{0.002}$ This can be rearranged a: $p=1.9MPa$
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