Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 215: 58

Answer

a) $v=92.16m/s$ b) $\alpha=34.56rad/s^2$

Work Step by Step

a) We are given the wheel's angular speed $\omega=288rad/s$ and its radius $r=0.32m$ The dragster has a rolling motion, so the dragster's linear speed is $$v=v_T=r\omega=92.16m/s$$ b) The dragster starts from rest, so $v_0=0$. We also know the distance $s=384m$. We can find the linear acceleration of the dragster: $$a=\frac{v^2-v_0^2}{2s}=11.06m/s^2$$ Thanks to rolling motion, we also have $$a=a_T=r\alpha$$ $$\alpha=\frac{a}{r}=34.56rad/s^2$$
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