Answer
a) $\omega=45.5rad/s$
b) $v_T=7.96m/s$
Work Step by Step
a) We have the tire's linear speed $v=15m/s$ and radius $r=0.33m$
In rolling motion, $v=v_T=r\omega$, so $$\omega=\frac{v}{r}=45.5rad/s$$
b) The mentioned point has $r=0.175m$. Its tangential speed is $$v_T=r\omega=7.96m/s$$
