Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 115: 54


The tension in each cable has a magnitude of $4.26kN$.

Work Step by Step

As shown in the below photo, two tension forces in two cables, when translated into the vertical component, each has a magnitude of $T\sin\theta$. Opposing the tension forces is the weight of the I-beam. Since the I-beam is lifted at a constant velocity, these forces balance each other. $$mg=T\sin\theta+T\sin\theta=2T\sin\theta$$ $$T\sin70=\frac{mg}{2}=\frac{8kN}{2}=4kN$$ $$T=4.26kN$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.