Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems: 43

Answer

a) 1.6 $\times$ $10^{4}$ N b) 4.3 $\times$ $10^{3}$ N

Work Step by Step

a) Normal force = mg $\times$ cos(15) = 1700 $\times$ 9.8 $\times$ cos(15) $\approx$ 1.6 $\times$ $10^{4}$ N b) Static frictional force = mg $\times$ sin(15) = 1700 $\times$ 9.8 $\times$ sin(15) $\approx$ 4.3 $\times$ $10^{3}$ N
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.