Answer
2240.62 km
Work Step by Step
Speed of the airplane with respect to the ground while flying west,
$V_{PG}=240\space m/s-57.8\space m/s\approx182\space m/s$
We can get the time required to reach the turnaround point as follows.
$t_{1}=\frac{x}{182\space m/s}$
Speed of the airplane with respect to the ground while flying east,
$V_{PG}=240\space m/s+57.8\space m/s\approx298\space m/s$
We can get the time required to reach the home from the turnaround point as follows.
$t_{2}=\frac{x}{298\space m/s}$
Total time $=t_{1}+t_{2}=6\space h=21600\space s$
$\frac{x}{182\space m/s}+\frac{x}{298\space m/s}=21600\space s$
$x=2,440,620\space m\approx2440.62\space km$
Thus, distance from home = 2440.62 km
