Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems - Page 76: 60

Answer

$8.92^{\circ}$ South of west

Work Step by Step

Please see the attached image first. Let's take, The velocity of the plane relative to the ground = $V_{PG}$ The velocity of the plane relative to the air= $V_{PA}$ The velocity of the air relative to the ground = $V_{AG}$ According to the image, we can get. $sin\theta=\frac{V_{AG}}{V_{PA}}=\frac{38\space m/s}{245\space m/s}=>\theta=sin^{-1}(0.16)=8.92^{\circ}$ South of west
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