Answer
$8.92^{\circ}$ South of west
Work Step by Step
Please see the attached image first.
Let's take,
The velocity of the plane relative to the ground = $V_{PG}$
The velocity of the plane relative to the air= $V_{PA}$
The velocity of the air relative to the ground = $V_{AG}$
According to the image, we can get.
$sin\theta=\frac{V_{AG}}{V_{PA}}=\frac{38\space m/s}{245\space m/s}=>\theta=sin^{-1}(0.16)=8.92^{\circ}$ South of west