Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems - Page 76: 59

Answer

(a) 41 m/s, due east (b) -41 m/s, due west

Work Step by Step

Let's take, The velocity of train A relative to train B = $V_{AB}$ The velocity of train A relative to the ground = $V_{AG}$ The velocity of train B relative to the ground = $V_{BG}$ Taking east as the positive direction, we can get. (a)$V_{AB}=V_{AG}+V_{GB}=V_{AG}-V_{BG}$ ; Let's plug known values into this equation. $V_{AB}=13\space m/s-(-28\space m/s)=41\space m/s$ due east (b) $V_{BA}=-V_{AB}=-41\space m/s$ due west
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.