Answer
190 s
Work Step by Step
Let's take,
John's velocity relative to Chad = $V_{JC}$
John's velocity relative to the ground = $V_{JG}$
The ground's velocity relative to Chad = $V_{GC}$
Chad's velocity relative to the ground =$V_{CG}$
We can write,
$V_{JC}=V_{JG}+V_{GC}=V_{JG}-V_{CG}$ ; Let's plug known values here.
$V_{JC}=\space\uparrow 4.5\space m/s-\uparrow 4\space m/s=\space\uparrow 0.5\space m/s$
The time it makes for John $=\frac{95\space m}{V_{JC}}= \frac{95\space m}{0.5\space m/s}=190\space s$
to pass Chad
