Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems - Page 76: 53

Answer

(a) 2000 s, (b) 1800 m

Work Step by Step

Please see the attached image first. Let's take, Swimmer's velocity with respect to water = $V_{SW}$ Water velocity with respect to ground = $V_{WG}$ Swimmer's velocity with respect to ground = $V_{SG}$ (a) Let's apply the equation $S=ut$ to the swimmer with respect to water to find the time to cross the river. $S_{SW}=u_{SW}t$ ; Let's plug known values into this equation. $2800\space m=1.4\space m/s\times t$ $t=2000\space s$ (b) (a) Let's apply the equation $S=ut$ to the water with respect to the ground to find the distance x that the swimmer is carried downstream while crossing the river. $S_{WG}=u_{WG}t$ ; Let's plug known values into this equation. $x=0.91\space m/s\times 2000\space s=1800\space m$
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