Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 573: 7



Work Step by Step

$V=\frac{Energy}{Charge}=\frac{1.1\times10^{5}\,J}{Charge}=9.0\,V$ $\implies Charge=\frac{1.1\times10^{5}\,J}{9.0\,V}=1.2\times10^{4}\,C$ Current $I=\frac{Charge}{Time}=\frac{1.2\times10^{4}\,C}{(6\times3600)s}=0.56\,A$ According to Ohm's law, $R=\frac{V}{I}=\frac{9.0\,V}{0.56\,A}=16\,\Omega$
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