## Physics (10th Edition)

$16\,\Omega$
$V=\frac{Energy}{Charge}=\frac{1.1\times10^{5}\,J}{Charge}=9.0\,V$ $\implies Charge=\frac{1.1\times10^{5}\,J}{9.0\,V}=1.2\times10^{4}\,C$ Current $I=\frac{Charge}{Time}=\frac{1.2\times10^{4}\,C}{(6\times3600)s}=0.56\,A$ According to Ohm's law, $R=\frac{V}{I}=\frac{9.0\,V}{0.56\,A}=16\,\Omega$