Answer
$0.58\,\Omega$
Work Step by Step
Resistivity $\rho=2.82\times10^{-8}\,\Omega \cdot m$ (for aluminum)
Area $A= 4.9\times10^{-4}\,m^{2}$
Length $l=10\,km=10\times10^{3}\,m=10^{4}\,m$
Resistance $R=\rho \frac{l}{A}$
$=2.82\times10^{-8}\,\Omega \cdot m\times\frac{10^{4}\,m}{4.9\times10^{-4}\,m^{2}}=0.58\,\Omega$
