Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 573: 12


The wire is made with aluminum.

Work Step by Step

Length $l=2.80\,m$ Area $A=\pi r^{2}=\pi (1.03\times10^{-3}\,m)^{2}=3.33\times10^{-6}\,m^{2}$ $R=\frac{V}{I}=\frac{0.0320\,V}{1.35\,A}=0.0237\,\Omega$ Another equation for resistance is $R=\rho \frac{l}{A}$ Rearranging this equation, we get $\rho=\frac{RA}{l}=\frac{0.0237\,\Omega\times3.33\times10^{-6}\,m^{2}}{2.80\,m}=2.82\times10^{-8}\,\Omega\cdot m$ The material with resistivity equal to $2.82\times10^{-8}\,\Omega \cdot m$ is aluminum.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.