Answer
The wire is made with aluminum.
Work Step by Step
Length $l=2.80\,m$
Area $A=\pi r^{2}=\pi (1.03\times10^{-3}\,m)^{2}=3.33\times10^{-6}\,m^{2}$
$R=\frac{V}{I}=\frac{0.0320\,V}{1.35\,A}=0.0237\,\Omega$
Another equation for resistance is
$R=\rho \frac{l}{A}$
Rearranging this equation, we get
$\rho=\frac{RA}{l}=\frac{0.0237\,\Omega\times3.33\times10^{-6}\,m^{2}}{2.80\,m}=2.82\times10^{-8}\,\Omega\cdot m$
The material with resistivity equal to $2.82\times10^{-8}\,\Omega \cdot m$ is aluminum.
