Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 573: 22

Answer

$1.0\times10^{2}\Omega$

Work Step by Step

V= 120 V P= 140 W We know that P= $\frac{V^{2}}{R}$ Thus, we find: R= $\frac{V^{2}}{P}=\frac{(120V)^{2}}{140 W}\approx 1.0\times10^{2} \Omega$
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